QUOTE (Tom Poje @ Mar 30 2006, 05:07 AM)

I have seen a further argument that says there is only one avg ben % test - that consists of all employees, even if otherwise excludable option was used anywhere. this would seem to fail based on 1.410(b)-5(d)(3) which says all plans included in the testing group under 1.410(b)-7(e)(1) AND ONLY THOSE PLANS are taken into account.
So far, so good, although I think it is more complicated than what you are implying.
QUOTE (Tom Poje @ Mar 30 2006, 05:07 AM)

Personally I think this statement also supports the idea you could have an avg ben % test for the 401(k) portion that is different than the nonelective portion.
Oops. Now, re-read 1.410(b)-7(e)(1)(iii) and see if that doesn't change your mind.
In English, I believe that -7(e)(1) says something like the following:
Plans in the testing group include the plan being tested and any plan that can be permissively aggregated. You use the rules of (d) to determine what plans can be permissively aggregated. However, as you careen through (d), you do so with the knowledge that (d)(4) is to be ignored (QSLOB stuff); with the knowledge that (d)(5) is to be ignored (you aggregate a plan with a different plan year for this purpose (the ABPT) even though you can't normally aggregate such a plan for 410(b)/401(a)(4) testing); with the knowledge that the general rules of disaggregation ((d)(2)) are to be applied ignoring the fact that k/m/ESOP plans are mandatorily disaggregated (in other words, k/m/ESOPs are not mandatorilly disaggregated for this purpose).
If a k/m/ESOP is not mandatorily disaggregated then it is, by definition, part of the testing group because the testing group includes all plans of the employer that can be permissively aggregated.
That is, it includes all plans of the employer other than plans that are mandatorilly disaggregated.
If a k/m/ESOP is not mandatorilly disaggregated, then, by definition, it is a plan that can be permissively aggregated, at least for this purpose.
So, for ABT purposes, you absolutely must include k/m/ESOP's.
By extension, since 1.410(b)-7(e)(1)(iii) only references ©(1) through ©(2) (that is, it does not reference ©(1) through ©(3)), we absolutely know that when doing this test, we treat the portion of a plan benefitting otherwise excludables as mandatorilly disaggregated from the portion of the plan that benefits those who are not otherwise excludable (and vice-versa). To get here is not straightforward, though, because it requires reading the last sentence of (d)(2). That sentence says to go back to yet another section for rules on how to test otherwise excludable employees. That is 1.410(b)-6(b)(3)(ii).
So, the sequence is to look at 1.410(b)-7(e)(1)(iii) which back references 1.410(b)-7©(1) and -7©(2) and note that -7©(3) is not back referenced.
I'm not sure whether all of this is a triple-negative or a quadruple-negative. It is surely not as simple as a mere double-negative.